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0.6x^2-6x+12.6=0
a = 0.6; b = -6; c = +12.6;
Δ = b2-4ac
Δ = -62-4·0.6·12.6
Δ = 5.76
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-\sqrt{5.76}}{2*0.6}=\frac{6-\sqrt{5.76}}{1.2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+\sqrt{5.76}}{2*0.6}=\frac{6+\sqrt{5.76}}{1.2} $
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